參數(shù)資料
型號: K4T1G044QC-ZCLE6
元件分類: DRAM
英文描述: 256M X 4 DDR DRAM, 0.45 ns, PBGA60
封裝: ROHS COMPLIANT, FBGA-60
文件頁數(shù): 4/26頁
文件大?。?/td> 487K
代理商: K4T1G044QC-ZCLE6
DDR2 SDRAM
K4T1G044QC
K4T1G084QC
Rev. 1.1 June 2007
12 of 26
7.6 Differential input AC logic Level
Note :
1. VID(AC) specifies the input differential voltage |VTR -VCP | required for switching, where VTR is the true input signal (such as CK, DQS, LDQS or UDQS)
and VCP is the complementary input signal (such as CK, DQS, LDQS or UDQS). The minimum value is equal to V IH (AC) - V IL(AC).
2. The typical value of VIX(AC) is expected to be about 0.5 * VDDQ of the transmitting device and VIX(AC) is expected to track variations in VDDQ .
VIX(AC) indicates the voltage at which differential input signals must cross.
7.7 Differential AC output parameters
Note :
1. The typical value of VOX(AC) is expected to be about 0.5 * VDDQ of the transmitting device and VOX(AC) is expected to track variations in VDDQ .
VOX(AC) indicates the voltage at which differential output signals must cross.
8.0 ODT DC electrical characteristics
Note1: Test condition for Rtt measurements
Measurement Definition for Rtt(eff): Apply VIH (ac) and VIL (ac) to test pin separately, then measure current I(VIH (ac)) and I( VIL (ac)) respectively. VIH
(ac), VIL (ac), and VDDQ values defined in SSTL_18
Measurement Definition for VM: Measure voltage (VM) at test pin (midpoint) with no load.
Symbol
Parameter
Min.
Max.
Units
Notes
VID(AC)
AC differential input voltage
0.5
VDDQ + 0.6
V
1
VIX(AC)
AC differential cross point voltage
0.5 * VDDQ - 0.175
0.5 * VDDQ + 0.175
V
2
Symbol
Parameter
Min.
Max.
Units
Note
VOX(AC)
AC differential cross point voltage
0.5 * VDDQ - 0.125
0.5 * VDDQ + 0.125
V
1
PARAMETER/CONDITION
SYMBOL
MIN
NOM
MAX
UNITS
NOTES
Rtt effective impedance value for EMRS(A6,A2)=0,1; 75 ohm
Rtt1(eff)
60
75
90
ohm
1
Rtt effective impedance value for EMRS(A6,A2)=1,0; 150 ohm
Rtt2(eff)
120
150
180
ohm
1
Rtt effective impedance value for EMRS(A6,A2)=1,1; 50 ohm
Rtt3(eff)
40
50
60
ohm
1
Deviation of VM with respect to VDDQ/2
delta VM
- 6
+ 6
%
1
VDDQ
Crossing point
VSSQ
VTR
VCP
VID
VIX or VOX
< Differential signal levels >
Rtt(eff) =
V
IH (ac) - VIL (ac)
I(V
IH (ac)) - I(VIL (ac))
delta VM =
2 x Vm
VDDQ
x 100%
- 1
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