參數(shù)資料
型號: ADE7758ARWZRL
廠商: ANALOG DEVICES INC
元件分類: 模擬信號調(diào)理
英文描述: Poly Phase Multifunction Energy Metering IC with Per Phase Information
中文描述: SPECIALTY ANALOG CIRCUIT, PDSO24
封裝: LEAD FREE, MS-013-AD, SOIC-24
文件頁數(shù): 30/68頁
文件大?。?/td> 1584K
代理商: ADE7758ARWZRL
ADE7758
Voltage RMS Gain Adjust
The ADC gain in each phase of the voltage channel can be
adjusted for the rms calculation by using the voltage rms gain
registers (AVRMSGAIN, BVRMSGAIN, and CVRMSGAIN).
The gain of the voltage waveforms before LPF1 is adjusted by
writing twos complement, 12-bit words to the voltage rms gain
registers. The expression below shows how the gain adjustment
is related to the contents of the voltage gain register.
Rev. A | Page 30 of 68
+
×
=
12
2
VRMSGAIN
Gain
without
Values
RMS
Nominal
Register
VRMS
of
Content
1
For example, when 0x7FF is written to the voltage gain register,
the ADC output is scaled up by 50%.
0x7FF = 2047d, 2047/2
12
= 0.5
Similarly, 0x800 = –2047d (signed twos complement) and the
ADC output is scaled by –50%.
ACTIVE POWER CALCULATION
Electrical power is defined as the rate of energy flow from
source to load. It is given by the product of the voltage and
current waveforms. The resulting waveform is called the
instantaneous power signal and it is equal to the rate of energy
flow at every instant of time. The unit of power is the watt or
joules/sec. Equation 5 gives an expression for the instantaneous
power signal in an ac system.
(
t
VRMS
t
v
ω
×
×
=
sin
2
( )
)
(3)
( )
(
)
t
IRMS
2
i
ω
×
×
=
sin
(4)
where
VRMS
= rms voltage,
IRMS
= rms current.
( )
( )
( )
t
i
v
p
×
=
t)
(2
VRMS
IRMS
VRMS
MS
R
I
(t)
p
ω
×
×
×
=
cos
(5)
The average power over an integral number of line cycles (n) is
given by the expression in Equation 6.
( )
IRMS
VRMS
dt
p
nT
1
p
nT
0
×
=
=
(6)
where
t
is the line cycle period.
P is referred to as the active or real power. Note that the active
power is equal to the dc component of the instantaneous power
signal
p
(
t
) in Equation 5, that is,
VRMS
×
IRMS
. This is the
relationship used to calculate the active power in the ADE7758
for each phase. The instantaneous power signal
p
(
t
) is generated
by multiplying the current and voltage signals in each phase.
The dc component of the instantaneous power signal in each
phase (A, B, and C) is then extracted by LPF2 (the low-pass
filter) to obtain the average active power information on each
phase. Figure 64 shows this process. The active power of each
phase accumulates in the corresponding 16-bit watt-hour
register (AWATTHR, BWATTHR, or CWATTHR). The input to
each active energy register can be changed depending on the
accumulation mode setting (see Table 17).
0
INSTANTANEOUS
POWER SIGNAL
p(t) = VRMS
×
IRMS – VRMS
×
IRMS
×
cos(2
ω
t)
ACTIVEREALPOWER
SIGNAL=VRMS
IRMS
0x19999A
VRMS
×
IRMS
0xCCCCD
0x00000
CURRENT
i(t) = 2
×
IRMS
×
sin(
ω
t)
VOLTAGE
v(t) = 2
×
VRMS
×
sin(
ω
t)
Figure 64. Active Power Calculation
Because LPF2 does not have an ideal “brick wall” frequency
response (Figure 65), the active power signal has some ripple
due to the instantaneous power signal. This ripple is sinusoidal
and has a frequency equal to twice the line frequency. Because
the ripple is sinusoidal in nature, it is removed when the active
power signal is integrated over time to calculate the energy.
0
0
–4
–8
–12
d
–16
–20
–24
1
3
10
8
FREQUENCY (Hz)
30
100
Figure 65. Frequency Response of the LPF Used
to Filter Instantaneous Power in Each Phase
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