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ADE7753
–26–
REV. PrF 10/02
PRELIMINARY TECHNICAL DATA
C AL IBR AT ING T HE E NE R GY ME T E R
When calibrating the ADE7753, the first step is to calibrate
the frequency on CF to some required meter constant, e.g.,
3200 imp/kWh.
A convenient way to to determine the output frequency on CF
is to use the line cycle energy accumulation mode. As shown
in Figure 37, DFC generates a pulse each time a LSB in the
LAENERGY register is accumulated. CF frequency (before
the CF frequency divider) can be conveniently determined by
the following expression:
Time
Elasped
r
0] Registe
:
3
LAENERGY[2
of
Content
Frequency
CF
=
When the CYCMODE (bit 7) bit in the Mode register is set
to a logic one, energy is accumulated over an integer number
of half line cycles. If the line frequency is fixed and the
number of half cycles of integration is specified, the total
elasped time can be calculated by the following:
cycles
half
of
number
f
2
1
×
Time
Elasped
l
×
=
For example, at 60Hz line frequency, the elasped time for
255 half cycles will be 2.125 seconds. Rewriting the above in
terms of contents of various ADE7753 registers and line
frequencies (
fl
):
0]
:
LINECYC[15
fl
2
0]
:
3
LAENERGY[2
Frequency
CF
×
×
=
(24)
where
f
l
is the line frequency.
Alternatively, CF frequency can be calculated based on the
average L PF2 output.
27
2
CLKIN
×
Output
LPF2
Average
=
Frequency
CF
(25)
C alibrating the F requency at C F
When the frequency before frequency division is known, the
pair of C F F requency D ivider registers (C F NUM and
CFDEN) can be adjusted to produce the required frequency
on CF. In this example a meter constant of 3200 imp/kWh
is chosen as an appropriate constant. T his means that under
a steady load of 1kW, the output frequency on CF would be,
kWh
imp
CF
Frequency
60
min
60
×
Assuming the meter is set up with a test current (basic
current) of 20A and a line voltage of 220V for calibration, the
load is calculated as 220V
×
20A = 4.4kW. T herefore the
expected output frequency on C F under this steady load
condition would be 4.4
×
0.8888H z = 3.9111H z.
Under these load conditions the transducers on Channel 1
and Channel 2 should be selected such that the signal on the
voltage channel should see approximately half scale and the
signal on the current channel about 1/8 of full scale (assuming
a maximum current of 80A). Assuming at line frequency of
60Hz, energy is accumulated over FFh number of half line
cycles, the resulting content of the LAENERGY register will
be approximately 2971.4 (decimal). CF frequency is there-
fore calculated to be:
Hz
8888
.
3600
3200
sec
/
3200
)
(
=
=
=
1398.3Hz
=
255
60
×
2
×
4
971
2
=
(CF)
Frequency
Alternatively, the average value from LPF2 under this con-
dition is approximately 1/16 of the full-scale level. As
described previously, the average LPF2 output at full-scale
ac input is CCCCD (hex) or 838,861 (decimal). At 1/16 of
full-scale, the LPF2 output is then 52,428.81. T hen using
Digital to Frequency Conversion, the frequency under this
load is calculated as:
3.579545MH
×
52428.81
=
CF)
Frequency(
27
Hz
3
398
1
=
2
z
T his is the frequency with the contents of the CFNUM and
CFDEN registers equal to 000h. T he desired frequency out
is 3.9111Hz. T herefore, the CF frequency must be divided
by 2797/3.9111Hz or 357.5 decimal. T his is achieved by
loading the pair of C F Divider registers with the closest
rational number. In this case, the closest rational number is
found to be 1/358 (or 1h/166h). T herefore, 0h and 165h
should be written to the C FNUM and C FDEN registers
respectively. Note that the CF frequency is multiplied by the
contents of (CFNUM + 1) / (CFDEN + 1). With the CF
D ivide registers contents equal to 1h/166h, the output
frequency is given as 2797Hz / 358 = 3.905Hz. T his setting
has an error of -0.1%.
Calibrating CF is made easy by using the Calibration mode
on the ADE7753. T he critical part of this approach is that the
line frequency needs to be exactly known. If this is not
possible, the frequency can be measured by using the PE-
RIOD register of the ADE7753.
Note that changing WGAIN[11:0] register will also affect
the output frequency from CF. T he WGAIN register has a
gain adjustment of 0.0244% / LSB.
D etermine the kWHr/L SB C alibration C oefficient
T he Active Energy register (AENERGY ) can be used to
calculate energy. A full description of this register can be
found in the
Energy Calculation
section. T he AENERGY reg-
ister gives the user both sign and magnitude information
regarding energy consumption. On completion of the C F
frequency output calibration, i.e., after adjusting the C F
Frequency divider and the Watt Gain (WGAIN) register, the
second stage of the calibration is to determine the kWh/LSB
coefficient for the AENERGY register. Equation 26 below
shows how LAENERGY can be used to calculate the calibra-
tion coefficient.
fl
2
0]
:
3
LAENERGY[2
0]
×
:
LINECYC[15
seconds/Hr
3600
kW)
(in
Power
n
Calibratio
kWHr/LSB
×
×
=
(26)
Once the coefficient is determined, the MCU can compute
the energy consumption at any time by reading the AENERGY
contents and multiplying by the coefficient to calculate kWh.
In the above example, at 4.4kW, after 255 half cycles (at
60Hz), the resulting L AENERGY is approximately 2971
decimal. T he kWHr/LSB can therefore be calculated to be
8.74
×10
-7
kWHr/L SB using the above equation.