參數(shù)資料
型號: M25PE40VMW6G
廠商: STMICROELECTRONICS
元件分類: PROM
英文描述: 512K X 8 SPI BUS SERIAL EEPROM, PDSO8
封裝: 0.208 INCH, ROHS COMPLIANT, PLASTIC, SOP-8
文件頁數(shù): 46/62頁
文件大小: 565K
代理商: M25PE40VMW6G
DC and AC parameters
M25PE40
Table 21.
AC characteristics (50 MHz operation, T9HX (0.11m) process(1))(2)
Test conditions specified in Table 14 and Table 15
Symbol
Alt.
Parameter
Min.
Typ.
Max.
Unit
fC
Clock frequency for the following instructions:
FAST_READ, RDLR, PW, PP, WRLR, PE, SE,
SSE, DP, RDP, WREN, WRDI, RDSR, WRSR
D.C.
50
MHz
fR
Clock frequency for READ instructions
D.C.
33
MHz
tCH
(3)
tCLH Clock High time
9
ns
tCL
tCLL
Clock Low time
9
ns
Clock Slew Rate (peak to peak)
0.1
V/ns
tSLCH
tCSS S Active Setup time (relative to C)
5
ns
tCHSL
S Not Active Hold time (relative to C)
5
ns
tDVCH
tDSU Data In Setup time
2
ns
tCHDX
tDH
Data In Hold time
5
ns
tCHSH
S Active Hold time (relative to C)
5
ns
tSHCH
S Not Active Setup time (relative to C)
5
ns
tSHSL
tCSH S Deselect time
100
ns
tSHQZ
(4)
tDIS
Output Disable time
8
ns
tCLQV
tV
Clock Low to Output Valid under 30 pF/10 pF
8/6
ns
tCLQX
tHO
Output Hold time
0
ns
tWHSL
(5)
Write Protect Setup time
50
ns
tSHWL
Write Protect Hold time
100
ns
S to Deep Power-down
3
s
tRDP
S High to Standby mode
30
s
tW
Write Status Register cycle time
3
15
ms
tPW
(6)
Page Write cycle time (256 bytes)
11
23
ms
Page Program cycle time (256 bytes)
0.8
3ms
Page Program cycle time (n bytes)
int(n/8) × 0.025(7)
tPE
Page Erase cycle time
10
20
ms
tSE
Sector Erase cycle time
1.5
5
s
tSSE
Subsector Erase cycle time
80
150
ms
tBE
Bulk Erase cycle time
8
10
s
1.
2.
Details of how to find the technology process in the marking are given in AN1995, see also Section 13: Ordering
3.
tCH + tCL must be greater than or equal to 1/ fC.
4.
Value guaranteed by characterization, not 100% tested in production.
5.
Only applicable as a constraint for a WRSR instruction when SRWD is set to ‘1’.
6.
When using PP and PW instructions to update consecutive bytes, optimized timings are obtained with one sequence
including all the bytes versus several sequences of only a few bytes (1
≤ n ≤ 256).
7.
int(A) corresponds to the upper integer part of A. For instance, int(12/8) = 2, int(32/8) = 4 int(15.3) =16.
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