參數(shù)資料
型號: SA1630
廠商: NXP Semiconductors N.V.
英文描述: IF Quadrature Transceiver(IF正交收發(fā)器)
中文描述: 中頻正交收發(fā)器(中頻正交收發(fā)器)
文件頁數(shù): 25/36頁
文件大小: 477K
代理商: SA1630
Philips Semiconductors
Application note
AN2003
SA1630 IF transceiver demonstration board
1999 Jan 05
25
Transmit output equations
The transmit output is simply the I mixer output summed with the Q mixer output. Combining Equations (31) and (36) gives:
Tx output
= 2A I(0) sin
ω
c
t + 2B I(0) cos
ω
c
t + A I cos
ω
l
t – A I cos
ω
h
t
+ B I sin
ω
h
t – B I sin
ω
l
t + G Q(0) cos
ω
c
t +
1
/
2
G Q cos
ω
l
t
+
1
/
2
G Q cos
ω
h
t
From this equation we can group the terms by frequency. There are three different frequencies: the upper sideband
ω
h
; the lower sideband
ω
l
;
and the carrier frequency
ω
c
.
(37)
Tx output = Carrier (C) + upper sideband (USB) + lower sideband (LSB)
(38)
C = 2A I(0) sin
ω
c
t + 2B I(0) cos
ω
c
t + G Q(0) cos
ω
c
t
USB = – A I cos
ω
h
t + B I sin
ω
h
t +
1
/
2
G Q cos
ω
h
t
LSB = A I cos
ω
l
t – B I sin
ω
l
t +
1
/
2
G Q cos
ω
l
t
(39)
(40)
(41)
Where again A and B are the factors which incorporate the gain and phase error and are defined as:
A =
1
/
2
GG
e
cos
Θ
B =
1
/
2
GG
e
sin
Θ
ω
h
=
ω
c
+
ω
bb
ω
l
=
ω
c
ω
bb
(42)
(43)
(44)
(45)
Ideal case
In order to gain some insight into how this Tx modulation scheme provides the required single-sideband suppressed carrier output signal, let’s
first take a look at the Tx output equations under ideal conditions.
Let’s assume the following:
G
e
= 1 (channel mixer gains and baseband input signal amplitudes are perfectly matched)
Θ
= 0 (there is no quadrature phase error)
(46)
(47)
I(0) = Q(0) = 0 (there is no input offset error)
(48)
I = Q = M (the baseband input signal amplitudes are equal)
(49)
Substituting Equations (46) and (47) into Equations (42) and (43) gives:
A =
1
/
2
G * 1 * cos 0 =
1
/
2
G
B =
1
/
2
G * 1 * sin 0 = 0
(50)
(51)
Substituting Equation (48) into Equation (39) gives:
C = 0 + 0 + 0 = 0
(52)
Substituting Equations (49), (50), and (51) into equation (40) gives:
USB = –
1
/
2
G M cos
ω
h
t + 0 +
1
/
2
G M cos
ω
h
t = 0
(53)
Substituting Equations (49), (50), and (51) into equation (41) gives:
LSB = +
1
/
2
G M cos
ω
l
t – 0 +
1
/
2
G M cos
ω
l
t = G M cos
ω
l
t
(54)
Equations (52), (53), and (54) suggest that under “ideal” conditions, the resulting transmit output signal contains the single lower sideband
signal with a magnitude equal to the magnitude of the ac input signal times the mixer gain. They also show that the carrier and upper sideband
signals are completely suppressed!
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