參數(shù)資料
型號(hào)： LT3579IUFD-1#PBF
廠商： LINEAR TECHNOLOGY CORP
元件分類： 穩(wěn)壓器
英文描述： SWITCHING REGULATOR, PQCC20
封裝： 4 X 5 MM, LEAD FREE, PLASTIC, MO-220, QFN-20
文件頁(yè)數(shù)： 7/40頁(yè)
文件大?。?/td> 503K
代理商： LT3579IUFD-1#PBF
LT3579/LT3579-1
15
35791f
applicaTions inForMaTion
Figure 8. Dual Inductor Inverting Converter – The Component
Values Given Are Typical Values for a 1.2MHz, 5V to –12V Inverting
Topology Using Coupled Inductors
DUAL INDUCTOR INVERTING CONVERTER COMPONENT
SELECTION – COUPLED OR UN-COUPLED INDUCTORS
Due to its unique FB pin, the LT3579 can work in a Dual
Inductor Inverting configuration as in Figure 8. Changing
the connections of L2 and the Schottky diode in the
SEPIC topology, results in generating negative output
voltages. This solution results in very low output voltage
ripple due to inductor L2 in series with the output. Output
disconnect is inherently built into this topology due to the
capacitor C1.
Table 3 is a step-by-step set of equations to calculate
componentvaluesfortheLT3579whenoperatingasaDual
InductorInvertingconverterusingcoupledinductors.Input
parameters are input and output voltage, and switching
frequency (VIN, VOUT and fOSC respectively). Refer to the
Appendix for further information on the design equations
presented in Table 3.
Variable Definitions:
VIN = Input Voltage
VOUT = Output Voltage
DC = Power Switch Duty Cycle
fOSC = Switching Frequency
IOUT = Maximum Output Current
IRIPPLE = Inductor Ripple Current
Table 3. Dual Inductor Inverting Design Equations
PARAMETERS/EQUATIONS
Step 1: Inputs
Pick VIN, VOUT, and fOSC to calculate equations below.
Step 2: DC
DC
| VOUT | + 0.5V
VIN + |VOUT |+0.5V – 0.27V
Step 3: L
LTYP =
VIN – 0.27V
(
) DC
fOSC 1.8A
LMIN =
VIN – 0.27V
(
) 2 DC – 1
(
)
4A
fOSC 1 – DC
(
)
LMAX =
VIN – 0.27V
(
) DC
fOSC 0.5A
(1)
(2)
(3)
Solve equations 1, 2, and 3.
Choose the higher value between LTYP and LMIN for L.
L should never exceed LMAX.
L = L1 = L2 for coupled inductors.
L = L1
L2 for un-coupled inductors.
Step 4: IRIPPLE
IRIPPLE =
VIN – 0.27V
(
)DC
fOSC L
Step 5: IOUT
IOUT = 6A –
IRIPPLE
2
1– DC
(
)
Step 6: D1
VR > VIN +|VOUT |;IAVG > IOUT
Step 7: C1
4.7F (typical) ; VRATING > VIN + |VOUT |
Step 8: COUT
COUT =
IRIPPLE
8
fOSC 0.005 |VOUT |
Step 9: CIN
CIN =CPWR +CVIN
CIN =
IRIPPLE
8 fOSC 0.005 VIN
+
6A DC
40 fOSC 0.005 VIN
Step 10: RFB
RFB =
| VOUT | + 9mV
83.3A
Step 11: RT
RT =
87.6
fOSC
–1; fOSC in MHz andRT in k
Note: The maximum design target for peak switch current is 6A and
is used in this table. The final values for COUT and CIN may deviate
from the above equations in order to obtain desired load transient
performance for a particular application.
VIN
5V
RT
72k
100k
COUT
10F
×2
RFB
144k
CF
27pF
L1
3.3H
L2
3.3H
D1
30V, 2A
C1
4.7F
SW1 SW2
VIN
RT
VC
CC
1nF
RC
20k
FAULT
SHDN
FB
CLKOUT
SS
SYNC
GND
GATE
LT3579
35791 F08
VOUT
–12V
1.2A
CSS
0.22F
CIN
22F
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