參數(shù)資料
型號(hào): EUA5202QIT
廠商: Electronic Theatre Controls, Inc.
英文描述: 2-W Stereo Audio Power Amplifier with Mute
中文描述: 2 - W型立體聲音頻功率放大器靜音
文件頁數(shù): 19/22頁
文件大?。?/td> 680K
代理商: EUA5202QIT
EUA5202
DS5202 Ver 1.4 Nov. 2004
Power Supply Decoupling, C
S
The EUA5202 is a high-performance CMOS audio
amplifier that requires adequate power supply
decoupling to ensure the output total harmonic distortion
(THD) is as low as possible. Power supply decoupling
also prevents oscillations for long lead lengths between
the amplifier and the speaker. The optimum decoupling
is achieved by using two capacitors of different types of
noise on the power supply leads. For higher frequency
transients, spikes, or digital hash on the line, a good low
equivalent – series - resistance (ESR) ceramic capacitor,
typically 0.1
μ
F placed as close as possible to the device
V
DD
lead works best. For filtering lower – frequency
noise signals, a larger aluminum electrolytic capacitor of
10
μ
F or greater placed near the audio power amplifier is
recommended.
Bypass Capacitor, C
B
The bypass capacitor, C
B
, is the most critical capacitor
and serves several important functions. During startup or
recovery from shutdown mode, C
B
determines the rate at
which the amplifier starts up. The second function is to
reduce noise produced by the power supply caused by
coupling into the output drive signal. This noise is from
the midrail generation circuit internal to the amplifier,
which appears as degraded PSRR and THD+N. Bypass
capacitor, C
B
, values of 0.1
μ
F to 1
μ
F ceramic of
tantalum low-ESR capacitors are recommended for the
best THD and noise performance.
In Figure 2, the full feature configuration, two bypass
capacitors are used. This provides the maximum
separation between right and left drive circuits.When
absolute minimum cost and/or component space is
required, one bypass capacitor can be used as shown in
Figure 1. It is critical that terminals 6 and 19 be tied
together in this configuration.
Output Coupling Capacitor, C
C
In the typical single-supply SE configuration, and output
coupling capacitor (C
C
) is required to block the dc bias
at the output of the amplifier thus preventing dc currents
in the load. As with the input coupling capacitor and
impedance of the load form a high-pass filter governed
by equation 6
fc(high)= ---------------------------- (6)
C
L
The main disadvantage, from a performance standpoint,
is the load impedances are typically small, which drives
the low-frequency corner higher degrading the bass
response. Large values of
C
C
are required to pass low
frequencies into the load. Consider the example where a
C
C
of 330
μ
F is chosen and loads vary from 3
, 4
, 8
,
32
, 10k
, to 47k
. Table 1 summarizes the frequency
response characteristics of each configuration.
Table1. Common Load Impedances vs Low Frequency Output
Characteristics in SE Mode
R
L
3
4
8
32
10000
47000
C
C
330
μ
F
330
μ
F
330
μ
F
330
μ
F
330
μ
F
330
μ
F
Lowest Frequency
161 Hz
120 Hz
60 Hz
15 Hz
0.05 Hz
0.01 Hz
As Table 1 indicates, most of the bass response is
attenuated into 4–
load, an 8–
load is adequate,
headphone response is good, and drive into line level
inputs (a home stereo for example) is exceptional.
Using Low-ESR Capacitors
Low-ESR capacitors are recommended throughout this
applications section. A real (as opposed to ideal)
capacitor can be modeled simply as a resistor in series
with an ideal capacitor. The voltage drop across this
resistor minimizes the beneficial effects of the capacitor
in the circuit. The lower the equivalent value of this
resistance
the more the real capacitor behaves like an
ideal capacitor.
Bridged-tied Load Versus Single-ended Mode
Figure 56 show a linear audio power amplifier (APA) in
a BTL configuration. The EUA 5202 BTL amplifier
consists of two linear amplifiers driving both ends of the
load. There are several potential benefits to this
differential drive configuration, but initially consider
power to the load. The differential drive to the speaker
means that as one side is slewing up, the other side is
slewing down, and vice versa. This in effect doubles the
voltage swing on the load as compared to a ground
referenced load. Plugging 2
×
V
O(PP)
into the power
equation, where voltage is squared, yields 4 × the output
power from the same supply rail and load impedance
(see equation 7 )
O(PP)
V
(rms)
Power
------ (7)
L
V
R
2
V
1
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