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參數(shù)資料
| 型號(hào)： | CX74038-12 |
| 廠商： | SKYWORKS SOLUTIONS INC |
| 元件分類： | XO, clock |
| 英文描述： | 2.6 GHz/800 MHz Dual Fractional-N/lnteger-N Frequency Synthesizer |
| 中文描述： | PLL FREQUENCY SYNTHESIZER, 2600 MHz, PDSO20 |
| 封裝： | 6.5 X 4.4 MM, 1 MM HEIGHT, TSSOP-20 |
| 文件頁(yè)數(shù)： | 9/12頁(yè) |
| 文件大?。?/td> | 114K |
| 代理商： | CX74038-12 |
DATA SHEET CX74038
Skyworks Solutions, Inc. Phone [781] 376-3000 Fax [781] 376-3100 sales@skyworksinc.com www.skyworksinc.com
6
January 31, 2005 Skyworks Proprietary and Confidential information Products and product information are subject to change without notice 101075I
Case 2: To achieve a desired FVCO_RF frequency of 1400 MHz using a crystal frequency of 13 MHz with operation
of the synthesizer in RF mode using the 8/9 prescaler (PS = 0). The crystal frequency does not need to be
divided further, since the maximum comparison frequency is 15 MHz. Divide the operating frequency by the
internal reference frequency to determine the value of NTotal:
NTotal
= 1400 MHz
13 MHz
=107.6923076
Subtract 3.5 from NTotal and remove the fractional portion of the result to determine N1:
107.6923076 – 3.5 = 104.1923076
N1 = 104 (decimal)
Fractional portion = 0.1923076 (decimal)
N1 = 000001101000 (binary)
D21 ------------D10 Register Address 112
Multiply the fractional portion of N1 by 256 and remove the fractional portion of the result to determine FN:
0.1923076 × 256 = 49.230746
FN = 49 (decimal)
FN = 00110001 (binary)
D9 -------D2 Register Address 112
Divide FN by 256 to determine the actual fractional portion:
49 = 0.1914962
256
Subtract this result from the fractional portion of N1:
0.1923076 – 0.1914062 = 0.0009014
Multiply this result by 2097152 (the 21-bit
Σ modulator value 221) and remove the fractional portion to determine
the ME:
0.0009014 × 2097152 = 1890.3728
ME = 1890 (decimal)
ME = 0011101100010 (binary)
D21 --------------D9 Register Address 012
In this example, N1 is greater than 64, the minimum divide ratio for the 8/9 prescaler.
C1455
Figure 5. Fractional-N Applications: Sample Calculation (2 of 2)
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