參數(shù)資料
型號(hào): TB62201AFG
元件分類(lèi): 運(yùn)動(dòng)控制電子
英文描述: STEPPER MOTOR CONTROLLER, 1.5 A, PDSO38
封裝: 0.450 INCH, 0.65 MM PITCH, PLASTIC, HSOP-36/38
文件頁(yè)數(shù): 18/89頁(yè)
文件大?。?/td> 1396K
代理商: TB62201AFG
TB62201AFG
2005-04-04
25
IC Power Dissipation
IC power dissipation is classified into two: power consumed by transistors in the output block and power consumed
by the logic block and the charge pump circuit.
(1) Power consumed by the Power Transistor (calculated with Ron
= 0.6 )
In Charge mode, Fast Decay mode, or Slow Decay mode, power is consumed by the upper and lower transistors
of the H bridges. The following expression expresses the power consumed by the transistors of a H bridge.
P (out) = 2 (Tr) × Iout (A) × VDS (V) = 2 × Iout^2 × Ron ......................................(1)
The average power dissipation for output under 4bit micro step operation (phase difference between phases A
and B is 90°) is determined by expression (1).
Thus, power dissipation for output per unit is determined as follows (2) under the conditions below.
Ron = 0.6 (@ 1.0 A)
Iout (Peak: max) = 1.0 A
VM = 24 V
VDD = 5 V
P (out) = 2 (Tr) × 1.0 (A)^2 × 0.60 () ................................................................. (2)
=1.20 (W)
(2) Power consumed by the logic block and IM
The following standard values are used as power dissipation of the logic block and IM at operation.
I (LOGIC) = 2 mA (typ.): /unit
I (IM3) = 12.5 mA (typ.): operation/unit
I (IM1) = 6.0 mA (typ.): stop/unit
The logic block is connected to VDD (5 V). IM (total of current consumed by the circuits connected to VM and
current consumed by output switching) is connected to VM (24 V). Power dissipation is calculated as follows :
P (Logic & IM) = 5 (V) × 0.002 (A) + 24 (V) × 0.0125 (A) .................................... (3)
= 0.31 (W)
(3) Thus, power dissipation for 1 unit (P) is determined as follows by (2) and (3) above.
P = P (out) + P (Logic & IM) = 1.51 (W)
Power dissipation for 1 unit at standby is determined as follows:
P (standby) = 24 (V) × 0.006 (A) + 5 (V) × 0.002 (A)
= 0.154 (W)
When one motor driving = 100 %, power dissipation is determined as follows:
P (all) = 1.51 (W) + 1.664 (W) = 1.66 (W)
For thermal design on the board, evaluate by mounting the IC.
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