參數(shù)資料
型號(hào): SP34063AEN
英文描述: 1.5A Buck/Boost/Inverting DC-DC Switching Regulator
中文描述: 1.5A降壓/升壓/負(fù)輸出DC - DC開(kāi)關(guān)穩(wěn)壓器
文件頁(yè)數(shù): 3/10頁(yè)
文件大?。?/td> 114K
代理商: SP34063AEN
3
Date: 1/11/05 SP34063A 1.5A Buck/Boost/Inverting DC-DC Switching Regulator Copyright 2005 Sipex Corporation
Unless otherwise noted, the following specifications apply for V
CC
= +5.0V, T
A
= -40 to 85
°
C.
ELECTRICAL CHARACTERISTICS
I
C
Output
I
C
driver - 7.0mA*
*The 100
resistor in the emitter of the driver device requires about 7.0 mA before the output switch conducts
Forced
β
of output switch:
Note 1: Low duty cycle pulse technique are used during test to maintain junction temperature as close to ambient
temperature as possible.
Note 2: If the output switch is driven into hard saturation (non-Darlington configuration) at low switch currents (
300mA)
and high driver currents (
30mA), it may take up to 2.0
μ
s for it to come out of saturation. This condition will shorten the
off time at frequencies 30KHz, and is magnified at high temperatures. This condition does not occur with a Darlington
configuration, since the output switch cannot saturate. If a non-Darlington configuration is used, the following output drive
condition is recommended.
R
E
T
E
M
A
R
A
P
L
O
B
M
Y
S
.
N
I
M
.
P
Y
T
.
X
A
M
S
T
N
U
S
N
O
I
D
N
O
C
r
o
t
s
O
y
c
n
e
u
q
e
F
F
C
S
O
0
3
8
3
5
4
z
H
K
F
n
0
=
T
C
,
V
0
=
o
5
2
n
V
T
A
C
5
=
t
e
C
e
g
h
C
I
G
H
C
0
3
8
3
5
4
μ
A
V
T
A
C
C
,
V
6
3
o
V
0
5
2
=
C
o
=
t
e
C
e
g
h
c
s
D
I
G
H
C
S
I
D
0
8
1
0
4
2
0
9
2
μ
A
V
T
A
C
C
,
V
6
3
o
V
0
5
2
=
C
o
=
t
e
C
e
g
h
C
o
e
g
h
n
c
s
o
R
D
I
G
H
C
S
I
D
I
G
H
C
2
5
5
V
o
7
n
,
C
C
T
A
C
o
5
2
=
e
g
a
V
e
s
n
e
S
t
m
i
t
e
C
V
)
s
n
e
s
K
P
I
0
5
2
0
0
3
0
5
3
V
m
I
G
H
C
I
=
G
H
C
S
I
D
T
,
A
C
o
5
2
=
)
e
o
n
(
h
c
w
S
t
u
p
t
u
O
n
o
n
D
)
s
E
,
g
a
V
V
n
n
o
S
n
n
o
C
C
o
e
V
)
T
A
S
(
E
C
-
0
3
V
I
W
S
o
c
8
,
s
n
,
A
0
e
e
n
=
d
n
)
e
n
e
g
a
V
n
o
S
V
)
T
A
S
(
E
C
-
5
4
7
V
I
W
S
V
o
2
8
=
8
2
n
R
d
β
,
A
0
c
F
=
,
C
C
e
0
=
n
G
t
e
C
C
D
h
E
F
0
5
5
7
-
I
W
S
T
A
V
,
A
C
o
0
5
2
=
=
E
C
,
V
0
=
t
e
C
e
S
-
O
r
e
C
I
C
)
-
1
0
0
0
1
μ
A
V
E
C
V
6
3
=
r
o
t
r
a
p
m
o
C
e
g
a
V
d
h
s
e
T
V
H
T
5
2
2
0
5
2
5
7
2
V
T
A
C
o
5
2
=
1
2
0
5
2
9
2
T
A
C
o
5
8
o
C
o
0
4
=
e
n
e
g
a
V
d
h
s
e
T
e
R
n
o
g
R
E
N
I
G
E
4
5
V
m
V
C
C
V
6
3
o
V
0
=
t
e
C
s
a
t
p
n
I
B
I
0
2
0
0
4
A
n
V
N
I
V
0
=
e
c
e
D
l
o
T
t
e
C
y
p
u
S
I
C
C
4
A
m
V
0
n
C
C
=
T
C
,
V
6
3
o
V
0
=
,
n
7
V
=
C
C
V
>
5
n
V
,
H
T
10
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