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參數(shù)資料
| 型號： | PQ7VZ5 |
| 廠商： | Sharp Corporation |
| 英文描述： | Variable Output, Compact Surface Mount Type Low Power-Loss Voltage Regulators |
| 中文描述： | 可變輸出，小型表面貼裝型低功率損耗穩(wěn)壓器 |
| 文件頁數(shù)： | 2/5頁 |
| 文件大?。?/td> | 43K |
| 代理商： | PQ7VZ5 |
Low Power-Loss Voltage Regulators
PQ7VZ5
Fig.4
Overcurrent Protection
Characteristics(Typical Value)
T
a
=25C
V
O
=3V(R
1
=1k
,R
2
=1.4k
)
Parameter
Symbol
V
IN
V
O
R
eg
L
R
eg
I
RR
V
i
-o
V
ref
T
C
V
ref
V
C (ON)
I
C (ON)
V
C (OFF)
I
C (OFF)
I
q
I
qs
Condition
-
-
Input voltage
Output voltage variable range
Load regulation
Line regulation
Ripple rejection
Dropout voltage
Reference voltage
Temperature coefficient of reference voltage
ON-state voltage for control
ON-state current for control
OFF-state voltage for control
OFF-state current for control
Quiescent current
Output OFF-state consumption current
*4
In case of opening control terminal
2
, output voltage turns off.
Unit
V
V
%
%
dB
V
V
%
V
μ
A
V
μ
A
mA
μ
A
MAX.
10.0
7.0
2.0
2.5
-
0.5
1.275
-
-
200
0.8
2
7
5
TYP.
-
-
0.2
0.2
60
-
1.25
±1.0
-
-
-
-
4
-
NIN.
3.4
1.5
-
-
45
-
1.225
-
2.0
-
-
-
-
-
I
Electrical Characteristics
(Unless otherwise specified, conditions shall be V
IN
=5V, V
O
=3V(R
1
=1k
), Io=0.3A, V
C
=2.7V, T
a
=25C)
I
O
=5mA to 0.5A
V
IN
=4 to 10V, I
O
=5mA
Refer to Fig. 2
V
IN
=3.4, I
O
=0.3A
-
I
O
=5mA, T
j
=0 to 125C
*4
-
I
C
=0A
V
C
=0.4V, I
C
=0A
I
C
=0A
V
C
=0.4V
Fig.1
Test Circuit
Fig.3
Power Dissipation vs. Ambient
Temperature
P
D
:With infinite heat sink
0
-20
0
Ambient temperature T
a
(C)
Note) Oblique line portion:Overheat protection may
operate in this area.
P
D
80
50
100
150
5
10
P
D
(
0
0.5
Output current I
O
(A)
1.0
1.5
2.0
4
3
2
1
0
O
O
(
V
i
-O
=5V
V
i
-O
=2V
V
i
-O
=0.5V
V
i
-O
=1V
Fig.2
Test Circuit for Ripple Rejection
~
V
G
5
G
3
G
1
G
2
G
4
A
A
V
V
A
V
IN
V
C
I
q
1k
I
O
V
O
V
C
R
L
47
μ
F
0.33
μ
F
47
μ
F
+
R
2
R
1
G
5
G
3
G
1
G
2
G
4
V
IN
e
i
e
o
1k
I
O
R
L
0.33
μ
F
47
μ
F
+
R
2
R
1
+
V
O
=V
ref
X
1+
-
1.25
X
1+
-
1
R
2
2
R
1
[R
1
=390
,V
ref
1.25V]
f=120Hz (sine wave)
e
i
=0.5V
rms
I
O
=0.3A
RR=20 log (e
i
/e
o
)
V
IN
=5V
V
O
=3V (R
1
=1k
)
=
=
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