參數(shù)資料
型號: DSPIC33FJ256GP506ATE/MR
元件分類: 微控制器/微處理器
英文描述: 16-BIT, FLASH, 20 MHz, MICROCONTROLLER, PQCC64
封裝: 9 X 9 MM, 0.9 MM HEIGHT, LEAD FREE, PLASTIC, QFN-64
文件頁數(shù): 3/24頁
文件大小: 5106K
代理商: DSPIC33FJ256GP506ATE/MR
RP500x
11
Discontinuous mode and Continuous mode
When the output current (IOUT) is relatively small, topen < toff as illustrated in the above diagram. In this case,
the energy is charged in the inductor during the time period of ton and is discharged in its entirely during the time
period of toff, therefore ILmin becomes to zero (ILmin=0). When IOUT is gradually increased, eventually, topen
becomes to toff (topen=toff), and when IOUT is further increased, ILmin becomes larger than zero (ILmin>0). The
former mode is referred to as the discontinuous mode and the latter mode is referred to as continuous mode.
Discontinuous mode
Continuous mode
ILmax
ILmin
ton
toff
T=1/fosc
topen
IL
t
ILmax
ILmin
ton
toff
T=1/fosc
IL
Iconst
t
In the continuous mode, when Equation 1 is solved for ton and assumed that the solution is tonc,
tonc = t
× VOUT / VIN....................................................................................................... Equation 2
When ton<tonc, the mode is the discontinuous mode, and when ton=tonc, the mode is the continuous mode.
Output Current and selection of External components
The relation between the output current and external components is as follows:
When Pch Tr. of LX is ON:
(Wherein, Ripple Current p-p value is described as IRP, ON resistance of Pch Tr. and Nch Tr. of LX are
respectively described as RONP and RONN, and the DC resistor of the inductor is described as RL.)
VIN = VOUT + (RONP + RL)
× IOUT + L × IRP / ton ................................................................ Equation 3
When Pch Tr. of LX is "OFF" (Nch Tr. is "ON"):
L
× IRP / toff = RONN × IOUT + VOUT + RL × IOUT ............................................................... Equation 4
Put Equation 2 to Equation 1 and solve for ON duty of Pch transistor, DON = ton / (toff + ton),
DON = (VOUT + RONN
× IOUT + RL × IOUT) / (VIN + RONN × IOUT - RONP × IOUT)........................ Equation 5
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